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X^2+100X+101=0
a = 1; b = 100; c = +101;
Δ = b2-4ac
Δ = 1002-4·1·101
Δ = 9596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9596}=\sqrt{4*2399}=\sqrt{4}*\sqrt{2399}=2\sqrt{2399}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-2\sqrt{2399}}{2*1}=\frac{-100-2\sqrt{2399}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+2\sqrt{2399}}{2*1}=\frac{-100+2\sqrt{2399}}{2} $
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